工作用到文件上傳的功能，在這個分享下 ~~
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public class PictureController : Controller { private IHostingEnvironment hostingEnv; public PictureController(IHostingEnvironment env) { this.hostingEnv = env; } // GET: /<controller>/ public IActionResult Index() { return View(); } public IActionResult UploadFiles() { return View(); } [HttpPost] public IActionResult UploadFiles(IList<IFormFile> files) { long size = 0; foreach (var file in files) { var filename = ContentDispositionHeaderValue .Parse(file.ContentDisposition) .FileName .Trim('"'); //這個hostingEnv.WebRootPath就是要存的地址可以改下 filename = hostingEnv.WebRootPath + $@"\{filename}"; size += file.Length; using (FileStream fs = System.IO.File.Create(filename)) { file.CopyTo(fs); fs.Flush(); } } ViewBag.Message = $"{files.Count} file(s) /{ size}bytes uploaded successfully!"; return View(); } } |
view:
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<form asp-action="UploadFiles" asp-controller="Picture" method="post" enctype="multipart/form-data"> <input type="file" name="files" multiple /> <input type="submit" value="Upload Selected Files" /> </form> |
文件是上傳到wwwroot目錄文件下的，這我也看不太懂還在學習，歡迎大家交流~~
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下面是jquery ajax方式上傳的
post方式的action的z參數沒用 因為只有一個post方式的會404錯誤所以又加了一個get的action
Controller:
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public IActionResult UploadFilesAjax(){ return View();}[HttpPost]public IActionResult UploadFilesAjax(string z) { long size = 0; var files = Request.Form.Files; foreach (var file in files) { var filename = ContentDispositionHeaderValue .Parse(file.ContentDisposition) .FileName .Trim('"'); filename = @"C:\Users\lg.HL\Desktop" + $@"\{filename}"; size += file.Length; using (FileStream fs = System.IO.File.Create(filename)) { file.CopyTo(fs); fs.Flush(); } } string message = $"{files.Count} file(s) / { size}bytes uploaded successfully!"; return Json(message);} |
view
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<form method="post" enctype="multipart/form-data"> <input type="file" id="files" name="files" multiple /> <input type="button" id="upload" value="Upload Selected Files" /> </form> |
jquery
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<script type="text/javascript"> $(document).ready(function () { $("#upload").click(function (evt) { var fileUpload = $("#files").get(0); var files = fileUpload.files; var data = new FormData(); for (var i = 0; i < files.length ; i++) { data.append(files[i].name, files[i]); } $.ajax({ type: "POST", url: "/Picture/UploadFilesAjax", contentType: false, processData: false, data: data, success: function (message) { alert(message); }, error: function () { alert("There was error uploading files!"); } }); }); });</script> |
歡迎大家交流~ 以上就是本文的全部內容，希望對大家的學習有所幫助，也希望大家多多支持服務器之家。
原文鏈接：http://www.cnblogs.com/intro/p/6235396.html
