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服務(wù)器之家 - 編程語(yǔ)言 - JAVA教程 - 詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼)

詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼)

2020-07-12 15:33JackieZheng JAVA教程

這篇文章主要介紹了詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼) ,具有一定的參考價(jià)值,有需要的可以了解一下。

以前也用過(guò)爬蟲(chóng),比如使用nutch爬取指定種子,基于爬到的數(shù)據(jù)做搜索,還大致看過(guò)一些源碼。當(dāng)然,nutch對(duì)于爬蟲(chóng)考慮的是十分全面和細(xì)致的。每當(dāng)看到屏幕上唰唰過(guò)去的爬取到的網(wǎng)頁(yè)信息以及處理信息的時(shí)候,總感覺(jué)這很黑科技。正好這次借助梳理Spring MVC的機(jī)會(huì),想自己弄個(gè)小爬蟲(chóng),簡(jiǎn)單沒(méi)關(guān)系,有些小bug也無(wú)所謂,我需要的只是一個(gè)能針對(duì)某個(gè)種子網(wǎng)站能爬取我想要的信息就可以了。有Exception就去解決,可能是一些API使用不當(dāng),也可能是遇到了http請(qǐng)求狀態(tài)異常,又或是數(shù)據(jù)庫(kù)讀寫(xiě)有問(wèn)題,就是在這個(gè)報(bào)exception和解決exception的過(guò)程中,JewelCrawler(兒子的小名)已經(jīng)可以能夠獨(dú)立的爬取數(shù)據(jù),并且還有一項(xiàng)基于Word2Vec算法做個(gè)情感分析的小技能。

后面可能還會(huì)有未知的Exception等著解決,也有一些性能需要優(yōu)化,比如和數(shù)據(jù)庫(kù)的交互,數(shù)據(jù)的讀寫(xiě)等等。但是目測(cè)年內(nèi)沒(méi)有太多精力放這上面了,所以今天做一個(gè)簡(jiǎn)單的總結(jié),而且前兩篇主要側(cè)重的是功能和結(jié)果,這篇來(lái)說(shuō)說(shuō)JewelCrawler是如何誕生的,并將代碼放到Github上(源碼地址在文章最后),有興趣的可以關(guān)注下(僅供交流學(xué)習(xí),請(qǐng)勿他用,考慮下douban君。多一點(diǎn)真誠(chéng),少一點(diǎn)傷害)

 環(huán)境介紹

開(kāi)發(fā)工具:Intellij idea 14

數(shù)據(jù)庫(kù): Mysql 5.5 + 數(shù)據(jù)庫(kù)管理工具Navicat(可用來(lái)連接查詢(xún)數(shù)據(jù)庫(kù))

詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼)

語(yǔ)言:Java

Jar包管理:Maven

版本管理:Git 

目錄結(jié)構(gòu)

詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼)

其中

  com.ansj.vec是Word2Vec算法的Java版本實(shí)現(xiàn)

  com.jackie.crawler.doubanmovie是爬蟲(chóng)實(shí)現(xiàn)模塊,其中又包括

詳解Java豆瓣電影爬蟲(chóng)——小爬蟲(chóng)成長(zhǎng)記(附源碼)

有些包是空的,因?yàn)檫@些模塊還沒(méi)有用上,其中

  •     constants包是存放常量類(lèi)

  •     crawl包存放爬蟲(chóng)入口程序

  •     entity包映射數(shù)據(jù)庫(kù)表的實(shí)體類(lèi)

  •     test包存放測(cè)試類(lèi)

  •     utils包存放工具類(lèi)

 resource模塊存放的是配置文件和資源文件,比如

  •     beans.xml:Spring上下文的配置文件

  •     seed.properties:種子文件

  •     stopwords.dic:停用詞庫(kù)

  •     comment12031715.txt:爬取的短評(píng)數(shù)據(jù)

  •     tokenizerResult.txt:使用IKAnalyzer分詞后的結(jié)果文件

  •     vector.mod:基于Word2Vec算法訓(xùn)練的模型數(shù)據(jù)

test模塊是測(cè)試模塊,用于編寫(xiě)UT.

 數(shù)據(jù)庫(kù)配置

1. 添加依賴(lài)的包

JewelCrawler使用的maven管理,所以只需要在pom.xml中添加相應(yīng)的依賴(lài)就可以了

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<dependency>
 
  <groupId>org.springframework</groupId>
 
  <artifactId>spring-jdbc</artifactId>
 
  <version>4.1.1.RELEASE</version>
 
</dependency>
 
<dependency>
 
  <groupId>commons-pool</groupId>
 
  <artifactId>commons-pool</artifactId>
 
  <version>1.6</version>
 
</dependency>
 
<dependency>
 
  <groupId>commons-dbcp</groupId>
 
  <artifactId>commons-dbcp</artifactId>
 
  <version>1.4</version>
 
</dependency>
 
<dependency>
 
  <groupId>mysql</groupId>
 
  <artifactId>mysql-connector-java</artifactId>
 
  <version>5.1.38</version>
 
</dependency>
 
<dependency>
 
  <groupId>mysql</groupId>
 
  <artifactId>mysql-connector-java</artifactId>
 
  <version>5.1.38</version>
 
</dependency>

2. 聲明數(shù)據(jù)源bean

我們需要在beans.xml中聲明數(shù)據(jù)源的bean

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<context:property-placeholder location="classpath*:*.properties"/>
 
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
 
  <property name="driverClassName" value="${jdbc.driver}"/>
 
  <property name="url" value="${jdbc.url}"/>
 
  <property name="username" value="${jdbc.username}"/>
 
  <property name="password" value="${jdbc.password}"/>
 
</bean>

注意: 這里是綁定了外部配置文件jdbc.properties,具體數(shù)據(jù)源的參數(shù)從該文件讀取。

如果遇到問(wèn)題“SQL [insert into user(id) values(?)]; Field 'name' doesn't  have a default value;”解決方法是設(shè)置表的相應(yīng)字段為自增長(zhǎng)字段。

解析頁(yè)面遇到的問(wèn)題

對(duì)于爬到的網(wǎng)頁(yè)數(shù)據(jù)需要解析dom結(jié)構(gòu),拿到自己想要的數(shù)據(jù),期間遇到如下錯(cuò)誤

org.htmlparser.Node不識(shí)別

解決方法:添加jar包依賴(lài)

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<dependency>
 
  <groupId>org.htmlparser</groupId>
 
  <artifactId>htmlparser</artifactId>
 
  <version>1.6</version>
 
</dependency>

org.apache.http.HttpEntity不識(shí)別

解決方法:添加jar包依賴(lài)

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<dependency>
 
  <groupId>org.apache.httpcomponents</groupId>
 
  <artifactId>httpclient</artifactId>
 
  <version>4.5.2</version>
 
</dependency> 

當(dāng)然這是期間遇到的問(wèn)題,最后用的是Jsoup做的頁(yè)面解析。

 maven倉(cāng)庫(kù)下載速度慢

之前使用的是默認(rèn)的maven中央倉(cāng)庫(kù),下載jar包的速度很慢,不知道是我的網(wǎng)絡(luò)問(wèn)題還是其他原因,后來(lái)在網(wǎng)上找到了阿里云的maven倉(cāng)庫(kù),更新后,相比之前簡(jiǎn)直是秒下,吐血推薦。

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<mirrors>
 
  <mirror>
 
   <id>alimaven</id>
 
   <name>aliyun maven</name>
 
 
   <mirrorOf>central</mirrorOf>   
 
  </mirror>
 
</mirrors>

找到maven的settings.xml文件,添加這個(gè)鏡像即可。

讀取resource模塊下文件的一種方法

比如讀取seed.properties文件

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@Test
 
  public void testFile(){
 
    File seedFile = new File(this.getClass().getResource("/seed.properties").getPath());
 
    System.out.print("===========" + seedFile.length() + "===========" );
 
  }

有關(guān)正則表達(dá)式

使用regrex正則表達(dá)式的時(shí)候,如果匹配上了定義的Pattern,則需要先調(diào)用matcher的find方法然后才能使用group方法找到子串。直接調(diào)用group方法是沒(méi)有辦法找到你想要的結(jié)果的。

  我看了下上面Matcher類(lèi)的源碼 

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package java.util.regex;
 
import java.util.Objects;
 
public final class Matcher implements MatchResult {
 
  /**
 
   * The Pattern object that created this Matcher.
 
   */
 
  Pattern parentPattern;
 
 
 
  /**
 
   * The storage used by groups. They may contain invalid values if
 
   * a group was skipped during the matching.
 
   */
 
  int[] groups;
 
 
 
  /**
 
   * The range within the sequence that is to be matched. Anchors
 
   * will match at these "hard" boundaries. Changing the region
 
   * changes these values.
 
   */
 
  int from, to;
 
 
 
  /**
 
   * Lookbehind uses this value to ensure that the subexpression
 
   * match ends at the point where the lookbehind was encountered.
 
   */
 
  int lookbehindTo;
 
 
 
  /**
 
   * The original string being matched.
 
   */
 
  CharSequence text;
 
 
 
  /**
 
   * Matcher state used by the last node. NOANCHOR is used when a
 
   * match does not have to consume all of the input. ENDANCHOR is
 
   * the mode used for matching all the input.
 
   */
 
  static final int ENDANCHOR = 1;
 
  static final int NOANCHOR = 0;
 
  int acceptMode = NOANCHOR;
 
 
 
  /**
 
   * The range of string that last matched the pattern. If the last
 
   * match failed then first is -1; last initially holds 0 then it
 
   * holds the index of the end of the last match (which is where the
 
   * next search starts).
 
   */
 
  int first = -1, last = 0;
 
 
 
  /**
 
   * The end index of what matched in the last match operation.
 
   */
 
  int oldLast = -1;
 
 
 
  /**
 
   * The index of the last position appended in a substitution.
 
   */
 
  int lastAppendPosition = 0;
 
 
 
  /**
 
   * Storage used by nodes to tell what repetition they are on in
 
   * a pattern, and where groups begin. The nodes themselves are stateless,
 
   * so they rely on this field to hold state during a match.
 
   */
 
  int[] locals;
 
 
 
  /**
 
   * Boolean indicating whether or not more input could change
 
   * the results of the last match.
 
   *
 
   * If hitEnd is true, and a match was found, then more input
 
   * might cause a different match to be found.
 
   * If hitEnd is true and a match was not found, then more
 
   * input could cause a match to be found.
 
   * If hitEnd is false and a match was found, then more input
 
   * will not change the match.
 
   * If hitEnd is false and a match was not found, then more
 
   * input will not cause a match to be found.
 
   */
 
  boolean hitEnd;
 
 
 
  /**
 
   * Boolean indicating whether or not more input could change
 
   * a positive match into a negative one.
 
   *
 
   * If requireEnd is true, and a match was found, then more
 
   * input could cause the match to be lost.
 
   * If requireEnd is false and a match was found, then more
 
   * input might change the match but the match won't be lost.
 
   * If a match was not found, then requireEnd has no meaning.
 
   */
 
  boolean requireEnd;
 
 
 
  /**
 
   * If transparentBounds is true then the boundaries of this
 
   * matcher's region are transparent to lookahead, lookbehind,
 
   * and boundary matching constructs that try to see beyond them.
 
   */
 
  boolean transparentBounds = false;
 
 
 
  /**
 
   * If anchoringBounds is true then the boundaries of this
 
   * matcher's region match anchors such as ^ and $.
 
   */
 
  boolean anchoringBounds = true;
 
 
 
  /**
 
   * No default constructor.
 
   */
 
  Matcher() {
 
  }
 
 
 
/**
 
 * All matchers have the state used by Pattern during a match.
 
 */
 
Matcher(Pattern parent, CharSequence text) {
 
  this.parentPattern = parent;
 
  this.text = text;
 
 
 
  // Allocate state storage
 
  int parentGroupCount = Math.max(parent.capturingGroupCount, 10);
 
  groups = new int[parentGroupCount * 2];
 
  locals = new int[parent.localCount];
 
 
 
  // Put fields into initial states
 
  reset();
 
}
 
....
 
/**
 
 * Returns the input subsequence matched by the previous match.
 
 *
 
 * <p> For a matcher <i>m</i> with input sequence <i>s</i>,
 
 * the expressions <i>m.</i><tt>group()</tt> and
 
 * <i>s.</i><tt>substring(</tt><i>m.</i><tt>start(),</tt> <i>m.</i><tt>end())</tt>
 
 * are equivalent. </p>
 
 *
 
 * <p> Note that some patterns, for example <tt>a*</tt>, match the empty
 
 * string. This method will return the empty string when the pattern
 
 * successfully matches the empty string in the input. </p>
 
 *
 
 * @return The (possibly empty) subsequence matched by the previous match,
 
 *     in string form
 
 *
 
 * @throws IllegalStateException
 
 *     If no match has yet been attempted,
 
 *     or if the previous match operation failed
 
 */
 
public String group() {
 
  return group(0);
 
}
 
/**
 
 * Returns the input subsequence captured by the given group during the
 
 * previous match operation.
 
 *
 
 * <p> For a matcher <i>m</i>, input sequence <i>s</i>, and group index
 
 * <i>g</i>, the expressions <i>m.</i><tt>group(</tt><i>g</i><tt>)</tt> and
 
 * <i>s.</i><tt>substring(</tt><i>m.</i><tt>start(</tt><i>g</i><tt>),</tt> <i>m.</i><tt>end(</tt><i>g</i><tt>))</tt>
 
 * are equivalent. </p>
 
 *
 
 * <p> <a href="Pattern.html#cg">Capturing groups</a> are indexed from left
 
 * to right, starting at one. Group zero denotes the entire pattern, so
 
 * the expression <tt>m.group(0)</tt> is equivalent to <tt>m.group()</tt>.
 
 * </p>
 
 *
 
 * <p> If the match was successful but the group specified failed to match
 
 * any part of the input sequence, then <tt>null</tt> is returned. Note
 
 * that some groups, for example <tt>(a*)</tt>, match the empty string.
 
 * This method will return the empty string when such a group successfully
 
 * matches the empty string in the input. </p>
 
 *
 
 * @param group
 
 *     The index of a capturing group in this matcher's pattern
 
 *
 
 * @return The (possibly empty) subsequence captured by the group
 
 *     during the previous match, or <tt>null</tt> if the group
 
 *     failed to match part of the input
 
 *
 
 * @throws IllegalStateException
 
 *     If no match has yet been attempted,
 
 *     or if the previous match operation failed
 
 *
 
 * @throws IndexOutOfBoundsException
 
 *     If there is no capturing group in the pattern
 
 *     with the given index
 
 */
 
public String group(int group) {
 
  if (first < 0)
 
    throw new IllegalStateException("No match found");
 
  if (group < 0 || group > groupCount())
 
    throw new IndexOutOfBoundsException("No group " + group);
 
  if ((groups[group*2] == -1) || (groups[group*2+1] == -1))
 
    return null;
 
  return getSubSequence(groups[group * 2], groups[group * 2 + 1]).toString();
 
}
 
/**
 
 * Attempts to find the next subsequence of the input sequence that matches
 
 * the pattern.
 
 *
 
 * <p> This method starts at the beginning of this matcher's region, or, if
 
 * a previous invocation of the method was successful and the matcher has
 
 * not since been reset, at the first character not matched by the previous
 
 * match.
 
 *
 
 * <p> If the match succeeds then more information can be obtained via the
 
 * <tt>start</tt>, <tt>end</tt>, and <tt>group</tt> methods. </p>
 
 *
 
 * @return <tt>true</tt> if, and only if, a subsequence of the input
 
 *     sequence matches this matcher's pattern
 
 */
 
public boolean find() {
 
  int nextSearchIndex = last;
 
  if (nextSearchIndex == first)
 
    nextSearchIndex++;
 
 
 
  // If next search starts before region, start it at region
 
  if (nextSearchIndex < from)
 
    nextSearchIndex = from;
 
 
 
  // If next search starts beyond region then it fails
 
  if (nextSearchIndex > to) {
 
    for (int i = 0; i < groups.length; i++)
 
      groups[i] = -1;
 
    return false;
 
  }
 
  return search(nextSearchIndex);
 
}
 
 
 
/**
 
 * Initiates a search to find a Pattern within the given bounds.
 
 * The groups are filled with default values and the match of the root
 
 * of the state machine is called. The state machine will hold the state
 
 * of the match as it proceeds in this matcher.
 
 *
 
 * Matcher.from is not set here, because it is the "hard" boundary
 
 * of the start of the search which anchors will set to. The from param
 
 * is the "soft" boundary of the start of the search, meaning that the
 
 * regex tries to match at that index but ^ won't match there. Subsequent
 
 * calls to the search methods start at a new "soft" boundary which is
 
 * the end of the previous match.
 
 */
 
boolean search(int from) {
 
  this.hitEnd = false;
 
  this.requireEnd = false;
 
  from    = from < 0 ? 0 : from;
 
  this.first = from;
 
  this.oldLast = oldLast < 0 ? from : oldLast;
 
  for (int i = 0; i < groups.length; i++)
 
    groups[i] = -1;
 
  acceptMode = NOANCHOR;
 
  boolean result = parentPattern.root.match(this, from, text);
 
  if (!result)
 
    this.first = -1;
 
  this.oldLast = this.last;
 
  return result;
 
}
 
...
 
}

原因是這樣的:這里如果不先調(diào)用find方法,直接調(diào)用group,可以發(fā)現(xiàn)group方法調(diào)用group(int group),該方法的方法體中有if first<0,顯然這里這個(gè)條件是成立的,因?yàn)閒irst的初始值就是-1,所以這里會(huì)拋異常。但是如果調(diào)用find方法,可以發(fā)現(xiàn),最終會(huì)調(diào)用search(nextSearchIndex),注意這里的nextSearchIndex已被last賦值,而last的值為0,再跳轉(zhuǎn)到search方法中

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boolean search(int from) {
 
  this.hitEnd = false;
 
  this.requireEnd = false;
 
  from    = from < 0 ? 0 : from;
 
  this.first = from;
 
  this.oldLast = oldLast < 0 ? from : oldLast;
 
  for (int i = 0; i < groups.length; i++)
 
    groups[i] = -1;
 
  acceptMode = NOANCHOR;
 
  boolean result = parentPattern.root.match(this, from, text);
 
  if (!result)
 
    this.first = -1;
 
  this.oldLast = this.last;
 
  return result;
 
}

這個(gè)nextSearchIndex傳給了from,而from在方法體中被賦值給了first,所以,調(diào)用了find方法之后,這個(gè)的first就不在是-1,也就不是拋異常了。

源碼已經(jīng)上傳至百度網(wǎng)盤(pán):http://pan.baidu.com/s/1dFwtvNz

以上說(shuō)的問(wèn)題比較碎,都是在遇到問(wèn)題和解決問(wèn)題的時(shí)候的一些總結(jié)。在具體操作的時(shí)候還會(huì)遇到其他問(wèn)題,有問(wèn)題或者建議的話(huà)歡迎提出來(lái)^^。

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原文鏈接:http://www.cnblogs.com/bigdataZJ/p/doubanmovie3.html

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