在某些情況下熟悉SQL Server 通配符的使用可以幫助我們簡單的解決很多問題。
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
|
--使用_運算符查找Person表中以an結尾的三字母名字USEAdventureWorks2012;GOSELECT FirstName, LastNameFROM Person.PersonWHERE FirstName LIKE'_an'ORDER BY FirstName; ---使用[^]運算符在Contact表中查找所有名字以Al開頭且第三個字母不是字母a的人USEAdventureWorks2012;GOSELECT FirstName, LastNameFROM Person.PersonWHERE FirstName LIKE'Al[^a]%'ORDER BY FirstName; ---使用[]運算符查找其地址中有四位郵政編碼的所有Adventure Works雇員的ID和姓名USEAdventureWorks2012;GOSELECT e.BusinessEntityID, p.FirstName, p.LastName, a.PostalCodeFROMHumanResources.EmployeeAS eINNER JOIN Person.PersonAS pON e.BusinessEntityID= p.BusinessEntityIDINNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityIDINNER JOIN Person.AddressAS aON a.AddressID= ea.AddressIDWHERE a.PostalCodeLIKE'[0-9][0-9][0-9][0-9]'; |
結果集：
|
1
2
3
|
EmployeeID FirstName LastName PostalCode---------- --------- --------- ----------290 Lynn Tsoflias 3000 |
|
1
2
3
4
5
6
7
8
9
10
11
12
|
--將一張表中名字為中英文的區分出來（借鑒論壇中的代碼）create table tb(namenvarchar(20)) insert into tbvalues('kevin')insert into tbvalues('kevin劉')insert into tbvalues('劉') select *,'Eng'from tbwherepatindex('%[a-z]%',name)>0and(patindex('%[吖-坐]%',name)=0)union allselect *,'CN'from tbwherepatindex('%[吖-坐]%',name)>0andpatindex('%[a-z]%',name)=0union allselect *,'Eng&CN'from tbwhere(patindex('%[吖-坐]%',name)>0)andpatindex('%[a-z]%',name)>0 |
結果集：
|
1
2
3
4
5
6
7
|
name -------------------- ------kevin Eng劉 CNkevin劉 Eng&CN (3 row(s) affected) |
