今天有朋友問我一道面試題,有5個人搶5個紅包,可重復搶,用多線程程序實現,實現方式有多種,分享一下我的思路:應用了阻塞隊列的特性。
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
|
/** * Created by zhanglinqiang on 2016/6/23. */ public class MyTest { public static void main(String[] args) throws InterruptedException { LinkedBlockingQueue<LuckyMoney> luckyMoneys = new LinkedBlockingQueue<>(); List<FutureTask> futureTasks = new ArrayList<>(); //準備搶紅包 for ( int i = 0 ; i < 5 ; i++) { FutureTask<Object> futureTask = new FutureTask<>( new CatchLuckMoney(luckyMoneys, "name" + i), null ); new Thread(futureTask, "name" +i).start(); futureTasks.add(futureTask); } Thread.sleep( 5 ); //確保搶紅包線程準備就緒 Random random = new Random( 100 ); //發5個紅包 for ( int i = 0 ; i < 5 ; i++) { luckyMoneys.put( new LuckyMoney( "紅包" +i, random.nextInt( 100 )+ 1 )); } //等到紅包搶完 while (!luckyMoneys.isEmpty()){ Thread.sleep( 1 ); } //終止搶紅包線程 for (FutureTask futureTask : futureTasks) { futureTask.cancel( true ); } } } class CatchLuckMoney implements Runnable { public CatchLuckMoney(LinkedBlockingQueue<LuckyMoney> luckyMoneys, String name) { this .luckyMoneys = luckyMoneys; this .name = name; } private LinkedBlockingQueue<LuckyMoney> luckyMoneys; private String name; @Override public void run() { while (!Thread.currentThread().isInterrupted()) { LuckyMoney redPackage = null ; try { redPackage = luckyMoneys.take(); } catch (InterruptedException e) { // e.printStackTrace(); break ; } System.out.println(name + "搶到了-->" + redPackage); luckyMoneys.remove(redPackage); } System.out.println( "end>>>>>>>>>>>>>>>>>>>>>>>>>>>>" +Thread.currentThread().getName()); } } class LuckyMoney { public LuckyMoney(String name, Integer money) { this .name = name; this .money = money; } private String name; private Integer money; @Override public String toString() { return "LuckyMoney{" + "name='" + name + '\ '' + ", money=" + money + '}' ; } } |
運行效果:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
|
Connected to the target VM, address: '127.0.0.1:8869' , transport: 'socket' name3搶到了-->LuckyMoney{name= '紅包0' , money= 16 } name4搶到了-->LuckyMoney{name= '紅包3' , money= 89 } name0搶到了-->LuckyMoney{name= '紅包2' , money= 75 } name1搶到了-->LuckyMoney{name= '紅包1' , money= 51 } name3搶到了-->LuckyMoney{name= '紅包4' , money= 92 } end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name0 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name4 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name3 Disconnected from the target VM, address: '127.0.0.1:8869' , transport: 'socket' end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name1 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name2 Process finished with exit code 0 |
以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支持服務器之家。
原文鏈接:http://blog.csdn.net/u011411069/article/details/52503835